lab report experiment 14 identification of an unknown acid 1

first page

Introduction

The introduction must address these points

What is a titration? What is the purpose of a titration experiment?
What is a primary standard? What was the primary standard in this experiment? (If you didn’t use a primary standard, indicate what it should have been))
Why were there 2 standard solutions? That is, why wasnâ€™t NaOH(aq) used as a primary standard for titrating the unknown acid? (If you didn’t use a primary standard, then explain why NaOH(aq) should be used as a primary standard.
How would melting of a pure sample differ from melting of an impure sample?
What is Ka? What is pKa? What does a high Ka mean? What does a high pKa mean?
What is a buffer?
For a weak acid, under what conditions will pH = pKa?

second page

Results

Provide tables as indicated in the lab manual

Calculations

Write a sample calculation for each type of calculation
- Molar mass of unknown.
- Calculation for the half titration point.

third page

Discussion

Your grade will be largely assigned based on correct identification of your unknown. If you are fairly certain that you have misidentified your unknown acid, partial credit will be given if you explain the reason for the uncertainty and provide some plausible sources of error. Miscalculation is not a valid source of error.
You must list the following
- The identity of your unknown
  - Here is the list of possibilities (Links to an external site.)
- The experimental molar mass and calculated molar mass
- The experimental melting point for your unknown
- The experimental pKa for your unknown
- The literature melting point for your unknown (with a citation for the reference)
- The literature pKa for your unknown (with a citation for the reference)

Conclusion

Write a conclusion
- Remember to report your findings
- Remember to be quantitative
My obsevations to be used:( to be put in a table)
Part 1 titration of an uknown acid
initital buret reading trial 1 = 6.13ml trial 2 =7.12ml trial 3 = 8.20ml
final buret reading trial 1= 28.30ml trial 2=31.0 ml trial 3 = 29.50
mass of unknown trial 1= .2904g trial 2=.300g trial 3 = .303g
volume of base used: trial 1= 22.17 trial 2=23.88 trial 3= 21.3